-2x^2+11x+7=10+4x

Solution for -2x^2+11x+7=10+4x equation:

-2x^2+11x+7=10+4x

We move all terms to the left:

-2x^2+11x+7-(10+4x)=0

We add all the numbers together, and all the variables

-2x^2+11x-(4x+10)+7=0

We get rid of parentheses

-2x^2+11x-4x-10+7=0

We add all the numbers together, and all the variables

-2x^2+7x-3=0

a = -2; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·(-2)·(-3)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*-2}=\frac{-12}{-4}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*-2}=\frac{-2}{-4}
=1/2
$